Kindly see this image and solve it.
I solved this. But it form fourth power of equation. It is a 10th grade math. It seems any other techniq ond logic will apply please solve it. I didn't sleep whole night for this question
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I am going to prove that the only real solution of the equation:
$\sqrt\frac{x}{1-x}+\sqrt{1-x}=1$
is $x=0$.
Proof:
It is necessary that $x\in\left[0,1\right[$ in order that the values inside the two square roots are nonnegative.
Squaring both sides of the equation, we obtain:
$\frac{x}{1-x}+1-x+2\sqrt{x}=1$
$\frac{x}{1-x}-x+2\sqrt{x}=0$
$\frac{x-x+x^2}{1-x}+2\sqrt{x}=0$
$\frac{x^2}{1-x}+2\sqrt{x}=0$
But $\frac{x^2}{1-x}\ge0$ and $2\sqrt{x}\ge0$, so there is only a possibility which is:
$\frac{x^2}{1-x}=2\sqrt{x}=0$
Therefore $x=0$.
As a matter of fact $x=0$ is a real solution of the equation and it is actually the only one.