If $0<x,0<\alpha$, then $0<x^\alpha$
I know that If $x<y$ and $a>1$, then $a^x<a^y$
And I know the exponential laws.
How can I prove it without differentation?
2026-04-03 02:19:26.1775182766
If $0<x,0<\alpha$, then $0<x^\alpha$
20 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in REAL-ANALYSIS
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