If $A$ and $B$ are $n×n$ matrices, then $|A+B^T|=|A^T+B|$
can I prove that it's t/f without giving a value to the matrices?
If $A$ and $B$ are $n×n$ matrices, then $|A+B^T|=|A^T+B|$
can I prove that it's t/f without giving a value to the matrices?
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Nice two-liner solves this for you: $$\mathrm{det}(A) = \mathrm{det}(A^T)$$ $$\mathrm{det}(A+B^T) = \mathrm{det}([A+B^T])^T) = \mathrm{det}(A^T+B)$$
You can show $(A+B)^T = A^T + B^T$ in the middle there for a more complete proof.