In a circle with centre 'O', PA and PB are two chords. PC is the chord that bisects the angle APB. The tangent to the circle at C is drawn meeting PA and PB extended at Q and R respectively. If QC=3, QA=2 and RC=4, then length of RB equals?
I found its solution here but it assumes that the chord PC passes through centre O. Is it implied anywhere in question?