I have a block diagonal matrix A which has the same block B in its diagonal entries. Can we express A as a product of B*I, where I is an identity matrix?
2026-03-25 16:02:10.1774454530
If $A$ is block-diagonal with $B$ in its diagonal, can we write it as $A=B\otimes I$?
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It's not completely clear what you mean, but I think that the matrix $A$ that you're describing has the form $$ A = \pmatrix{ B & 0 & \cdots & 0\\ 0 & B & \ddots & \vdots \\ \vdots & \ddots & \ddots & 0\\ 0 & 0 & \cdots & B}. $$ If this is the case, then we can write $A = I \otimes B$ where $I$ is an identity matrix and $\otimes$ denotes the Kronecker product.