if $\alpha\leq\beta$ then there is $\gamma$ such as $\alpha+\gamma=\beta$

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I'm trying to prove the statement in the title, a.e existence of ordinal substraction. I think it can be done with transfinite induction, but do any of you have a better/easier way?

thanks

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HINT: Consider the unique $\gamma$ isomorphic to $\beta\setminus\alpha$.