We know that $e^e$ is not proved to be transcendent, so neither is the number $e^{ei\pi}$.
If $e^{ei\pi}$ turns out to be transcendent, can it be proved that $e^e$ is also?
We know that $e^e$ is not proved to be transcendent, so neither is the number $e^{ei\pi}$.
If $e^{ei\pi}$ turns out to be transcendent, can it be proved that $e^e$ is also?
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