If $g'(0)>0$ write this expression $\lim\limits_{x \to 0} \frac{\sin(f(x))}{\sin(g(x))}$ using $f(0),f'(0)$ and $g(0)$.
This came up in my Analysis 1 exam, and i couldn't do it.
If $g'(0)>0$ write this expression $\lim\limits_{x \to 0} \frac{\sin(f(x))}{\sin(g(x))}$ using $f(0),f'(0)$ and $g(0)$.
This came up in my Analysis 1 exam, and i couldn't do it.
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The expression is not determined if and only if $f(0)=g(0)=0$Use Hospital, the limit is
${{f'(0)cos(f(0)}\over{g'(0)cosg(0)}}={{f'(0)}\over{g'(0)}}.$