No. We know that the mean of the upper $10\%$ is nine times the mean of the lower $90\%$, but that is all. That also says the overall mean is $1.8$ times the mean of the lower $90\%$. We could have $9$ people with $1$ and $1$ person with $9$ for an overall mean of $1.8$ We could have $8$ people with $1$, $1$ people with $5$, and $1$ person with $13$. The mean is then $2.6$.
No. We know that the mean of the upper $10\%$ is nine times the mean of the lower $90\%$, but that is all. That also says the overall mean is $1.8$ times the mean of the lower $90\%$. We could have $9$ people with $1$ and $1$ person with $9$ for an overall mean of $1.8$ We could have $8$ people with $1$, $1$ people with $5$, and $1$ person with $13$. The mean is then $2.6$.