Let $A$ be a commutative ring with unit, and $P$ a prime ideal.
My question is:
If $I$ is an irreducible ideal in $A$, is $(I+P)/P$ irreducible in $A/P$? If not, can you show a counterexample?
Of course, if $(I+P)/P$ is reducible in $A/P$, then $I+P$ is reducible in $A$, because $$ \dfrac{I+P}{P} = \dfrac{J_1}{P} + \dfrac{J_2}{P} \Rightarrow I+P = J_1 + J_2 $$ but i don't think this is enough to conclude that $I$ is reducible.
Here is a counterexample:
$I=(xy-z)$ is irreducible (it is even prime) in $K[x,y,z]$, but $(I+(z))/(z)=(xy)$ is not irreducible in $K[x,y,z]/(z)=K[x,y]$.