The title pretty much says it all : from any point on a flat torus, there is at least one geodesic from that point that goes back to it. And, by definition of a flat torus, that geodesic is a line. So, if I look toward the direction pointed by that geodesic, do I see myself from behind ?
If the anwser is no, why ? I have very little knowledge about how a flat torus can not be embedded in $\mathbb{R}^3$ with full ($C^2$) regularity, so I suppose that we need to be at least in $\mathbb{R}^4$ for the question to make sense, but then maybe it is hard/not relevant to talk about light trajectory (obviously I am not considering any relativistic effect whatsoever).

Yes: if you're "in" the torus and light rays travel along its geodesics, then we can think of the torus as a flat square with its top & bottom and left & right edges identified. In terms of what you can see, it's equivalent to being in an infinite plane with a copy of yourself at each integer point; you see many copies of yourself from behind.
Edit: I think the answer is no to the question you mean to ask. Note that (per Wikipedia) the flat torus (e.g. as realized by the standard embedding in $\Bbb R^4$) is flat in the sense that the surface of a cylinder is flat, i.e. it has zero Gaussian curvature. Of course you don't see yourself from behind when standing on a cylinder in $\Bbb R^3$, and more generally, if you're in a Euclidean space where light travels in straight lines, then it doesn't matter what you're standing on, you won't see yourself from behind.