I am unable to define skewness and kurtosis, only with mean and standard deviation. Can we say, if the distribution has mean and standard deviation, which is equal to each other, is it an exponential distribution?
2026-03-26 17:31:36.1774546296
If mean is equal to standard deviation , then the distribution is always an exponential distribution?
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No. Starting from any distribution with a finite standard deviation, you can translate it by a constant (which does not change the standard deviation) to make its mean equal the standard deviation; this is clearly not going to be an exponential distribution in general.