$$\sum_{i=0}^n (a_i-u)^2 = sum $$ u = mean/average of the elements
where value of sum and n is given. Can we find value of each $a_i$?
$$\sum_{i=0}^n (a_i-u)^2 = sum $$ u = mean/average of the elements
where value of sum and n is given. Can we find value of each $a_i$?
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No. Suppose $n=2$. On the one hand, if $a_{0}=-1$ and $a_{1}=1$, then $\mu=0$ and $a_{0}^{2}+a_{1}^{2}=2$. On the other hand, if $a_{0}'=a_{1}'=0$, then $\mu'=0$ and $a_{0}'^{2}+a_{1}'^{2}=0$.
As @confused pointed out, the reason the $a_{i}$'s cannot be recovered is because you have one equation, but more than one unknown variable.