If $V:\mathbb{R}^2\rightarrow\mathbb{R}$ is $C^1$ and positive definite does its level curves form a continuum around the origin?

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Let $V:\mathbb{R}^2\rightarrow\mathbb{R}$ be continuously differentiable and positive definite. I'm currently reading a book where the authors claim that $V$ has a continuum of closed level curves around the origin. While I certainly find this to be plausible it is not immediately evident to me. How is this proven? If the proof is extensive a simple sketch will suffice and I will do my best to fill in the gaps.

Note that in this context $V$ being positive definite means that $V(\textbf{0})=0$ and $\textbf{x}\in\mathbb{R}^2\setminus\{\textbf{0}\}\Rightarrow V(\textbf{x}) > 0$.