If X is a random variable $ X : $$ \begin{bmatrix} -9 & -6 & -3 \\ 1/4 & 2/4 & 1/4\end{bmatrix}$
How I can find $X^c$ ?
This is what I think is correct?
$ X^c : $$ \begin{bmatrix} -9 & -6 & -3 \\ 3/4 & 2/4 & 3/4\end{bmatrix}$
2026-04-09 00:00:47.1775692847
If X is a random variable, what is non X
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It looks like you have been given a represention of the distribution for $X$ using a table of its support and corresponding probability mass. That is okay, but should have been mentioned, or labeled, to avoid confusion.
$$\left[\begin{array}{r:rrr} x & -9 & -6 & -3 \\ \mathsf P(X=x) & 1/4 & 2/4 & 1/4\end{array}\right]$$
The table you produced matches the support for $X$ to the probability mass for its complement. That appears to be what is required in as much as $X^c$ can be understood as the complement of random varible $X$.
$$\left[\begin{array}{r:rrr} x & -9 & -6 & -3 \\ \mathsf P(X\neq x) & 3/4 & 2/4 & 3/4\end{array}\right]$$
If it is a concern, you should not expect the probability masses of this table to sum to one, since the events are not disjoint. $X^c$ is not itself a random variable.