In a trapezium DEBC, with diagonals BE and DC, the area of triangle DEB = area of triangle DEC.

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Why is this so? I understand that they share a common length DE and that the perpendicular from B to DE = the perpendicular from C to DE. Am I missing something?

edit: DE // BC

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The area of the triangle is $\frac{1}{2}\times base \times height$. Since length of the base and height are same for both the triangles the area is also same.