In how many ways can 10 different things be distributed to 4 persons if 2 are to receive 2 things and the others are to receive 3 things?

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I have no idea how to answer this question, I did a lot of research on trying to figure it out but every answer is so different. I would prefer something along the lines of using combinations and explain each step please! thank you!

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Line up the people in an arbitrary order. One approach is to pick the two people who will get $3$ things each, which you can do in $4 \choose 2$ ways. Choose three things to give the first one, in $10 \choose 3$ ways. Choose three to give the second that gets three-how many ways? Choose two to give the first of the others-how many ways? Finally give the last two to the last person.