Knowing that log(a) = b can be written as 10^b = a
How can I use that towards this inequality:
4/(x^2) <= log(n)
The logarithm is of base 10.
2026-05-16 18:23:45.1778955825
Inequalities using logarithms
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It works the same way. This is because $a \leq log(b) \implies 10^a \leq 10^{log(b)} \implies 10^a \leq b$. We can put both sides of the inequality to the power of $10$ because $10^x$ is an increasing function.
As for your equation, we have $10^{\frac{4}{x^2}} \leq n$.