Inequality with conditions $\sum_{cyc}\cos(a\cos(b))\geq \sum_{cyc}\cos(a\cos(c))$

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it's an inequality by me :

Let $a,b,c>0$ such that $a+b+c=1$ and $a\geq b \geq c $ then we have : $$\sum_{cyc}\cos(a\cos(b))\geq \sum_{cyc}\cos(a\cos(c))$$

This inequality is very precise . I try Karamata's inequality because the function $f(x)=\cos(x)$ is concave on $[0,1]$ but we have with $a\geq b \geq c$ : $$a\cos(b)\leq a\cos(c)$$

So we are in the wrong way .

I try also approximation with (for $x\in(0,1)$ ):

$$1-\frac{x^2}{2}+\frac{x^4}{24}\geq\cos(x)\geq 1-\frac{x^2}{2}$$

Remains to show :

$$\sum_{cyc}\Big(1-\frac{(a\cos(c))^2}{2}+\frac{(a\cos(c))^4}{24}\Big)\leq \sum_{cyc}\Big(1-\frac{(a\cos(b))^2}{2}\Big)$$

I think this last inequality is true but now I'm stuck...

I would like a hint if you have.

Thanks a lot for sharing your time and knowledge .