Use the following breakdown to compute a student's grade:
$20\%$ for the midterm
$55\%$ for the test average
$25\%$ for the final exam
The student wants at least a B for the course. This means she needs a course grade of greater than or equal to an $80$. She earned an $84$ on the midterm and a $75$ for the test average. What does she need on the final exam to get at least a B for the course?
$$80 \leq \frac{84 + 75 + x.25}{3}?$$
Must write inequality, solve the inequality and answer with a sentence.
Assume that the student's grade includes $100$ scores:
The score for the midterm (called $x$) is counted $20$ times
The score for the test average (called $y$) is counted $55$ times
The score for the final exam (called $z$) is counted $25$ times
Then the overall average of the student is $\frac{20x+55y+25z}{100}$.
For this specific problem, we need to solve $\frac{84\times 20+ 75\times 55+ 25z}{100}\ge 80$.
Then we should have $5805+25z\ge 8000 \Rightarrow25z\ge8000-5805=2195\Rightarrow z\ge87.8$
You can make the conclusion from here.