How would one proceed in solving this difficult inequation with multiple absolute values? is there a way one should proceed ?
$$\frac{x}{||x|-2|} \le \frac{x-1}{|x-3|}$$
thanks
How would one proceed in solving this difficult inequation with multiple absolute values? is there a way one should proceed ?
$$\frac{x}{||x|-2|} \le \frac{x-1}{|x-3|}$$
thanks
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Hint
Discuss several cases: $$x\in(-\infty,-2)\cup(-2 ,0]\; ; \; x\in(0 ,2)\; ;\; x\in(2 ,3)\; ;\; x\in(3 ,+\infty)$$