I have having an issue identifying the inner function of this function:
$$f(g(x))=\frac{1}{\sqrt{x+1}}$$
I "need" to take the derivative of it; hence I have to identify the inner function. My current thinking is that the inner function is $\sqrt{x+1}$, and outer would be $\frac{1}{x}$.
Outer
$$\frac{1}{x}$$
Inner
$$\sqrt{x+1}$$
Is my answer to the identification of the outside and inner functions correct?
Those are two possible solutions for the inner and outer functions, however, if you are to apply the chain rule, I would suggest just using $(x+1)^\frac{-1}{2}$ for your chain rule