How do I put:
$\int_\gamma (z + \frac{1}{z})^{2n} \frac{dz} {z} $
In the form: $\int_\gamma \frac{f(z)}{(z-a)^{2n}} $
Initially I have gone for $f(z)=\frac {1}{z} $ but I cannot get the rest in that form any ideas?
2026-03-25 14:28:50.1774448930
Integral Cauchy formula
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Just take the LCM and separate the numerator and denominator $$f\left(z\right)=\left(z^{2 }+1 \right)^{2 n}\ $$ $$ \left(z \right)^{2 n+1 }=\left(z-0\right)^{2 n+1 }\ $$