Let $G$ be a $p$-divisible group over $\mathbb{Q}_p$. Suppose that $G_{\mathbb{C}_p}$ has a model over $\mathcal{O}_{\mathbb{C}_p}$.
Does $G$ have a model over $\mathbb{Z}_p$?
Let $G$ be a $p$-divisible group over $\mathbb{Q}_p$. Suppose that $G_{\mathbb{C}_p}$ has a model over $\mathcal{O}_{\mathbb{C}_p}$.
Does $G$ have a model over $\mathbb{Z}_p$?
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Just to get this off the unanswered list. This is false even if you replace $\mathbb{C}_p$ by a finite extension of $\mathbb{Q}_p$. When I want to think of concrete examples of $p$-divisible groups that are interesting (e.g. of height larger than $1$) then I often times think of abelian varieties.
In this case we can use the following well-known theorem of Grothendieck (see [1, Exp. IX, Thm. 5.13]):
So, in this light, a positive answer to your question would imply that an abelian variety with potentially good reduction has good reduction. But, of course, this is false:
Example: The elliptic curve $E:y^2=x^3+p$ over $\mathbb{Q}_p$ has additive bad reduction but $E_{\mathbb{Q}_p(\sqrt[3]{p})}$ has good reduction. So, $E[p^\infty]$ does not admit a model over $\mathbb{Z}_p$ but $E[p^\infty]_{\mathbb{Q}_p(\sqrt[3]{p})}$ admits a model over $\mathbb{Z}_p[\sqrt[3]{p}]$.
[1] A. Grothendieck, Groupes de monodromie en géometrie algébrique, LNM 288, 340, Springer–Verlag, New York, 1972-3.