How can I resolve the following indefinite integral using hypergeometric series?
$$ \int (x^3 + 1)^\frac{1}{3} \,dx $$
Wolfram Alpha indicates that the series of Appell are used, but how to get to this result?
Grateful!
How can I resolve the following indefinite integral using hypergeometric series?
$$ \int (x^3 + 1)^\frac{1}{3} \,dx $$
Wolfram Alpha indicates that the series of Appell are used, but how to get to this result?
Grateful!
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By expanding the integrand into its binomial series, and switching the order of summation and integration.