How to calculate the following integral :
$$\int_0^ \infty \frac {\log (\frac{1+ix}{1-ix})}{e^{2πx}-1} dx$$
Where, i is the unit imaginary number or iota .
2026-03-26 11:04:58.1774523098
Integrate $\int_0^\infty \frac{\log(\frac{1+ix}{1-ix})}{e^{2\pi x} - 1} dx$
102 Views Asked by user699758 https://math.techqa.club/user/user699758/detail AtRelated Questions in CALCULUS
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