Integrate with substitution $ \int \frac{x^3+1}{5x+\sqrt{6^2-x^2}}dx $

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I have a task to integrate the following integral: `

$$ \int \frac{x^3+1}{5x+\sqrt{6^2-x^2}}dx $$

and I tried to solve it, but do not know if my moves are correct.

1. $ u=\sqrt{6^2-x^2} $

$ u^2=6^2-x^2 $

$ u=6-x $

$ x=u-6 $

$ dx=(u-6)'du=du $

2. $ \int \frac{(u-6)^3 -1}{5(u-6)+u}du $

  1. Should I now substitute $t=u-6$ or what?