Here's the parametric equations:
$x = \sin (t)$ $y = \sin (2t)$
$ 0 \le t \le \frac{\pi}{2}$
(1) How would I find the area of the region bounded by the curve and the x axis. (2) Volume of the solid formed when rotated $2\pi$ radians about x axis.
Here's the parametric equations:
$x = \sin (t)$ $y = \sin (2t)$
$ 0 \le t \le \frac{\pi}{2}$
(1) How would I find the area of the region bounded by the curve and the x axis. (2) Volume of the solid formed when rotated $2\pi$ radians about x axis.
On
In this case, the ordinary formulas for the area and the volume are $\int^b_a y \ dx$ and $\pi\int^b_a y^2 \ dx$.
For parametric equations, you replace $y$ with $y(t)$, $dx$ with $x'(t)dt$, and the limits of integration with the corresponding $t$ values, just as using the substitution rule for definite integrals.
Took me a while, but solved. Was stuck in the integration part to be specific.