Let $K\geq 3$ and consider $K$ real numbers $\mu_1<\mu_2<...<\mu_K$.
Let $\delta_j\equiv \mu_{j+1}-\mu_j$ $\forall j \in \{1,...,K-1\}$.
For $h\in \{2,...,K-1\}$, consider the following set of conditions $$ \begin{aligned} &\delta_1+\delta_2+...+\delta_{h-3}+\delta_{h-2}+ \delta_{h-1} \neq \delta_{K-1},\\ &\delta_1+\delta_2+...+\delta_{h-3}+\delta_{h-2}\hspace{1.2cm} \neq \delta_{K-1}+\delta_{K-2},\\ &\delta_1+\delta_2+...+\delta_{h-3}\hspace{2.4cm} \neq \delta_{K-1}+\delta_{K-2}+\delta_{K-3},\\ &...\\ &\delta_1 \hspace{5.4cm}\neq \delta_{K-1}+\delta_{K-2}+\delta_{K-3}+...+\delta_{K-h-1}. \end{aligned} $$
For example, for $K=3$ we have $$ \begin{aligned} &\delta_1\neq \delta_2. \end{aligned} $$
For $K=4$ we have $$ \begin{aligned} &\delta_1\neq \delta_3,\\ & \delta_1+\delta_2 \neq \delta_3,\\ &\delta_1\neq \delta_3+\delta_2. \end{aligned} $$
For $K=5$ we have $$ \begin{aligned} &\delta_1\neq \delta_4,\\ & \delta_1+\delta_2 \neq \delta_4,\\ &\delta_1+\delta_2+\delta_3\neq \delta_4,\\ &\delta_1+\delta_2\neq \delta_4+\delta_3,\\ &\delta_1\neq \delta_4+\delta_3+ \delta_2,\\ & \delta_1\neq \delta_4+\delta_3\\ \end{aligned} $$ I would like to know whether these conditions can be linked to some geometric/linear algebra/graph theory concept. Somehow, they rule out some specific linear combinations with a sort of geometric path, but if I was asked to explain the above conditions in English I would not be able to do so. Could you help?
Note that $$\sum_{j=m}^n\delta_j = \mu_{n+1} -\mu_m,$$ since the middle terms cancel. We can then rewrite a condition $$\delta_1+\dots+\delta_h\neq \delta_i+\dots+\delta_{K-1}$$ with $1\leq h<i\leq K-1 $ as $$\mu_{h+1} - \mu_1 \neq\mu_K-\mu_i.$$ Rearranging yields that the sum of the first and last $\mu$ is different from the sum of any other pair of $\mu$'s (since $h$ and $i$ can be chosen arbitrarily), and different from any other $\mu$ doubled (take $h=i-1$).
This is a massive simplification IMO, but I don't know where this sort of thing would arise.