Inverse Laplace Transform including s^a

47 Views Asked by At

If I have the relation in the Laplace domain as below, then how can I have an inverse transform in the time domain?

H(s)=(K_1^(-a_1)(1/(s^a_1+K^(-a_1)))(K_2^(-a_2)(1/(s^a_2+K^(-a_2)))