inverse laplace transform of $ \frac{s^2 +1}{s^2+s-2} {e^{-2s}}$

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inverse laplace transform of $$ \frac{s^2 +1}{s^2+s-2} {e^{-2s}}$$

I tried solving it like that, but I'm not sure:

1- Apply partial fraction to the f(t) part: $$(\frac{2/3}{s-1} + \frac{-5/3}{s+2}) {e^{-2s}}$$

2.Do the inverse transform and the first shift: $${2/3}{e^{s+2}} + {-5/3}{e^{-2{s+2}}}$$

Is this correct ?