Inverse of a matrix expression after SVD

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Let: $UDV^T$ be the SVD decomposition of $A$; $\lambda\in\mathbb{R}$ and $I_n$ the identity matrix

Why is the following true?

$(VD^2V^T+\lambda I_n)^{-1} = V(D^2+\lambda I_n)^{-1}V^T$