Let me first introduce a defitinition.
Definition (Smooth Curve) Let $\gamma\colon [a,b] \to \mathbb{R}^2$ a curve (continous function). We call $\gamma$ a $C^k$-smooth curve if $\gamma'(t) \neq 0$ for all $t \in [a,b]$ and if it is of class $C^k$.
So if $\gamma$ is $C^k$-smooth with $k > 0$, using this definition, does there exist for each point $v \in \gamma$ on the curve a coordinate system for the plane in which some piece of the curve containing $v$ is the graph $y = f(x)$ of a continuous function? If yes, what should a lowest $k$ can be? I'm guessing $k=1$.
I've tried thinking/finding some counter-examples, but all the counter-examples I find aren't smooth (see simple closed curves, this post asks the same question but for simple closed curves). Also what is interesting about the post, was a comment by Daniel Fischer. He claimed that any simple closed curve with a convex interior is also locally a graph.
If there is not true, what extra conditions should I add for it be true?
Any help would be greatly appreciated. Thanks in advance!
Suppose you could parametrize your curve as $f(x,y)=0$. This could be very difficult to achieve explicitly, but once done, by the Implicit Function Theorem the assertion is valid for every point where $\frac{\partial f}{\partial y} \neq 0$.