Is Chapman-Kolmogorov equation equivalent to law of total probability?

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For a hidden Markov process $\{x_k\}_{k\in {\mathbb N}_0}$ with observations $\{y_k\}_{k\in {\mathbb N}_0}$, the Chapman-Kolmogorov equation is

$$p(x_k|y_0,\ldots,y_{k-1}) = \int_{{\mathcal X}_{k-1}} p(x_k|x_{k-1}) p(x_{k-1}|y_0,\ldots,y_{k-1}) {\mathrm d}x_{k-1}.$$

This form is very similar to the law of total probability. I think they are equivalent, am I right? Thanks!