Is $f'(a)$ Not same as Finding Derivative of $f(x)$ and Substituting $x=a$

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I got this doubt regarding the differentiability of function $f(x)$ at $x=0$ where

$$f(x)= \begin{cases} x^2 \sin\left(\frac 1 x\right) & x \ne 0\\ 0 & x=0 \end{cases} $$

We know that $f(x)$ is Differentiable at $x=0$ and the Slope of tangent at $x=0$ is Zero Since RHD = LHD

But i am getting confused of the notation many books use for RHD = LHD = $f'(a)$

Because $f'(a)$ is value of the function's Derivative at $x=a$ in this case we have

$$f'(x)=-\cos \left(\frac{1}{x}\right)+2x \sin\left(\frac{1}{x}\right)$$ So $f'(0)$ Does not exist. But since $f(x)$ is differentiable at $x=0$ the notation says $f'(0)=0$

So i need clarification in this ?

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When you found the expression for $f'(x)$, the expression you used for $f(x)$ isn't valid for $x = 0$. Therefore there is no reason to expect the expression you find for $f'(x)$ to be valid for $x = 0$ either.

For $x = 0$, it's better to turn to the definition: $$ f'(0) = \lim_{h\to 0}\,\frac{f(h) - f(0)}{h}\\ = \lim_{h\to 0}\,\frac{h^2\sin(1/h)}{h}\\ = \lim_{h\to 0}\,h\sin(1/h) = 0 $$ Here is a graph of the function $f$, close to the origin:

enter image description here

You can see how each wave oscillates wildly (I've stretched the $y$-axis some, so it's exaggerated), but as a whole the graph flattens out, as it's squeezed between the two parabolas $y = x^2$ and $y = -x^2$. This is the reason it can be differentiable at $0$ even though the expression for $f'(x)$ doesn't make sense or even has a limit as $x\to 0$.

As a second way to look at this, if I hadn't stretched out the $y$-axis in the graph above, all we would have seen would be a somewhat thick line along the $x$-axis. Which means that close to the origin, the line $y = 0$ is actually a good approximation to $f(x)$, close to $x = 0$. The existence of a line which is a good approximation, under a certain strictly defined sense of "good approximation" (basically, no matter how much I stretch the $y$-axis to make the approximation look bad, just zooming in will eventually make it look good again), is the definition of differentiable, and a notion which is readily generalized to higher dimensions.

This function is the standard example illustrating the difference between a a function being differentiable and a function being continuously differentiable.