Is it correct: natural-logarithm maps algebraic numbers to transcendentals and vice-verse, over the domain it is defined?

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Is it correct that the natural logarithm function maps algebraic numbers to transcendental and transcendental numbers to algebraic, other than 1? Of course, over the domain natural log is defined i.e. $(0,\infty)$?

i.e.

$$\ln:A^+ \rightarrow T \hspace{5 mm};\hspace{5 mm} \ln:T^+ \rightarrow A,$$

and$$\ln:A^+ \nrightarrow A \hspace{5 mm};\hspace{5 mm} \ln:T^+ \nrightarrow T.$$

where;

$A^+$ is the set of positive algebraic numbers except $1$.

$T^+$ is the set of positive transcendental numbers.

$T$ is the set of transcendental numbers.

$A$ is the set of algebraic numbers.

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It is impossible for cardinality reasons alone, since $\ln$ is injective, so it cannot map an uncountable set into a countable one.

It is true that $\ln$ maps positive algebraic numbers (except 1) to transcendental numbers, by the Lindemann–Weierstrass theorem. Every algebraic real number except $0$ is the logarithm of a positive transcendental number, but so are most transcendental numbers. For a concrete example, $e^\pi$ is a transcendental number whose logarithm is transcendental.