Is it possible to eliminate the inner sum to evaluate numerically?

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Any hints on how to simplify the following double sum to be able to find the sum at least numerically?

$$\sum_{n=2}^{\infty}\frac1{n(n^2-1)} \sum_{k=1}^\infty \frac{(k-1/n)^{2n-2}}{(k+1/n)^{2n+2}}$$

Series comes from quantum mechanics (2nd order perturbation theory).