Does anyone have any insight into the trig sum and difference formulas? The formulas in themselves are very elegant, but I don't really like the proofs that have been given, even the geometric proofs. I feel that none of them address the following points:
cos(A+B) = cosAcosB - sinAsinB
If you keep one angle constant in this formula, say angle A, and change angle B, why will it trace out the exact cosine curve, just displaced by angle A? This doesn't seem obvious at all from the formula.
Also, the geometric proof is nice, but it doesn't show (to me) why adding angle A to B is the same as adding angle B to A
Earlier today I asked if trigonometry could exist in one dimension, and I think the answer is yes
In another question on this site, someone brought up the idea of matrix multiplication - now I know the mechanics of it, but have literally no idea why it works
So, if anyone had any extra insight into this weird formula, that would really be greatly appreciated!! I realise that this question may seem very strange, maybe even stupid, but hopefully you see where I am sort of coming from. Thanks.
I have been scouring the net for quite a while now but haven't gained much intuition. I do have a sort of obsession with really trying to understand all the formulas that they teach me at high school (final year coming up), and in a way it has delayed my progression in the subject.
So I guess another question would be - is it even possible to gain a deep intuition into high school mathematics, so for example, to feel as natural manipulating these trig equations as multiplication, or manipulating logarithms for example.
I believe you will only be satisfied when you understand $\cos$ and $\sin$ as related to $\exp$ via:
$\cos(z) = \frac{1}{2} ( e^{iz} + e^{-iz} )$ for any $z \in \mathbb{C}$
$\sin(z) = \frac{1}{2i} ( e^{iz} - e^{-iz} )$ for any $z \in \mathbb{C}$
I still think that the best way to define them all is via their power series which arises naturally from solving the first and second order ordinary linear differential equations, which in turn arise from naturally occurring phenomena. Of course, to do so would require various concepts such as limits and differentiability, but it is in my opinion very well motivated. After that, you can proceed as in https://math.stackexchange.com/a/802678/21820, which gives all the fundamental properties, and periodicity especially arises as the path of $\exp(it)$ along the unit circle for real $t$.
Now with these it is immediately clear that the special characteristics of all the common trigonometric identities arise from the characteristics of the exponential function, in particular that $\exp(x+y) = \exp(x) \exp(y)$. You can try proving all of them by just converting them to the equivalent identities for the exponential function. For example here is the particular formula you asked about:
$\cos(a+b) = \frac{1}{2} ( e^{i(a+b)} + e^{-i(a+b)} ) = \frac{1}{2} ( e^{ia} e^{ib} + e^{-ia} e^{-ib} )$
$\cos(a) \cos(b) - \sin(a) \sin(b) = \frac{1}{4} ( e^{ia} + e^{-ia} ) ( e^{ib} + e^{-ib} ) + \frac{1}{4} ( e^{ia} - e^{-ia} ) ( e^{ib} - e^{-ib} )$
$ = \frac{1}{2} ( e^{ia} e^{ib} + e^{-ia} e^{-ib} )$
And if you only need real $a,b$:
$\cos(a+b) = Re(e^{i(a+b)}) = Re(e^{ia}e^{ib}) = Re(e^{ia}) Re(e^{ib}) - Im(e^{ia}) Im(e^{ib})$
$ = \cos(a) \cos(b) - \sin(a) \sin(b)$ where the third equality can be checked directly from the multiplication of complex numbers.
Concerning your side question about matrix multiplication, left-multiplication of a matrix with a vector corresponds to some linear transformation of a vector. To get the desired property that the product of two matrices corresponds to the (non-commutative) composition of the corresponding linear transformations, we necessarily have to define the matrix multiplication exactly the way you have been taught. You should derive it for yourself to see that it is indeed the only way.