I would like to know if it is possible to simplify this expression, I have tried a lot, but I have not been able to do it.
\begin{equation}\text{diag}(V_{pn}) \text{diag}^{-1}((I-M)V_{pn})\end{equation}
Where $V_{pn}$ is a given variable:
\begin{equation} V_{pn} = \begin{pmatrix} V1p \\ V1n \\ \vdots \\ VNp \\ VNn \end{pmatrix} \end{equation}
I is the identity matrix, and M is an auxiliary matrix given by:
\begin{gather} \mathbf{M}=\begin{pmatrix} 0 & 1 & \dots & 0 & 0 \\ 1 & 0 & \dots & 0 & 0\\ \vdots & \vdots & \ddots & \vdots & \vdots\\ 0 & 0 & \dots & 0 & 1\\ 0 & 0 & \dots & 1 & 0 \end{pmatrix}\\ \end{gather}
Naturally I-M is a singular matrix; however the variables in $V_{pn}$ with Vp are strictly positive, and with Vn strictly negative. Thank you in advance.