Is it possible to solve $n=\text{floor}\left(\frac{L-1}{k}\right)$ for $L$?

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Is it possible to solve $$n=\text{floor}\left(\frac{L-1}{k}\right), n,k,L \in \mathbb{Z}^+$$ for $L$?

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Hint: $$n \leq \frac{L-1}{k}<n+1$$