Is $\mathsf{HA}$ the ind-completion of $\mathsf{FinHA}$

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We know that the category of Boolean algebras and homomorphisms is the ind-completion of $\mathsf{FinBA}$, the full subcategory of $\mathsf{BA}$ of finite Boolean algebras. I am wondering if the same holds for the category $\mathsf{HA}$ of Heyting algebras and Heyting morphisms.

Since Heyting algebras are models of an algebraic theory we know that it has filtered colimits. But I don't know how to prove that every Heyting algebra is the colimit of the diagram of its finite subalgebras.

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It's not true that every Heyting algebra is the filtered colimit of its finite subalgebras. Very generally, a finitary algebraic structure is the filtered colimit of its finite substructures iff every finitely generated substructure is finite. But not every finitely generated Heyting algebra is finite (in fact, even a Heyting algebra generated by just one element can be infinite; here is a picture of the free Heyting algebra on one generator).

The ind-completion of the category of finite Heyting algebras is the category of "locally finite" Heyting algebras, the Heyting algebras for which every finitely generated subalgebra is finite.