My method:
$Pr(A|B,C)=\frac{Pr(A,B,C)}{Pr(B,C)}=\frac{Pr(A,B)Pr(A,C)}{Pr(B)Pr(C)}=Pr(A|B)Pr(A|C)$. Is that okay?
My method:
$Pr(A|B,C)=\frac{Pr(A,B,C)}{Pr(B,C)}=\frac{Pr(A,B)Pr(A,C)}{Pr(B)Pr(C)}=Pr(A|B)Pr(A|C)$. Is that okay?
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No. $A\cap B$ and $A\cap C$ are not necessarily independent when $B$ and $C$ are.
Let $\Omega=\{1,2,3,4,5,6,7,8\}$ with uniform probability distribution.
Let $B=\{1,2,3,4\}, C=\{3,4,5,6\}, A=\{1,2,3\}$ Then ....