I Know that all the norms are equivalent in R, so every distance deduced by a norm makes R complete. But what about the other distances ? A proof or a controexample would be appreciate
2026-03-27 05:37:40.1774589860
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Is R complete to every distance?
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Another example would be $d(x,y)=|e^{-x}-e^{-y}|$, and $x_n=n$ (easier to work with).
Then: $$d(x_m,x_n)=|e^{-m}-e^{-n}|\le e^{\min(m,n)}\to 0$$ as $m,n\to\infty$, so $x_n$ is Cauchy, and assuming $x_n\to x\in\mathbb R$ one gets $d(x_n,x)\to 0$, so: $$|e^{-m}-e^{-x}|\to|0-e^{-x}|=e^{-x}=0$$ which is of course impossible.
As I said in the comments, take $d(x,y) = |\arctan x - \arctan y|$. Check it is a distance. Take now $s_n = n, n \in \mathbb{N}$. Is it Cauchy? does it converge?