Is Stirling's Approximation used here, to prove the asymptotic inequalities?

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Define $N_c=[\dfrac{1}{2}n\log n+cn]$ where $[.]$ denotes the greatest integer function, and $c$ is any arbitrary fixed real constant. Also, let $M={n\choose 2}$.

Then prove, for large $n$, the following inequalities:

$$\large{n\choose s}\dfrac{{{M - s(n-s)}\choose N_c}}{M\choose N_c}\leq \dfrac{e^{(3-2c)s}}{s!}\space\space\space\space\text{for } s\leq\dfrac{n}{2}$$

and $$\large{n\choose s}\dfrac{{{M - s(n-s)}\choose N_c}}{M\choose N_c}\leq \dfrac{e^{(3-2c)(n-s)}}{(n-s)!}\space\space\space\space\text{for } s\geq\dfrac{n}{2}$$

Here, $s$ is a positive integer such that $s<n-\dfrac{2N_c}{n}$.

I admit, these inequalities are a bit strange. But, I am convinced that these are simply estimates. The paper I am referring to, simply says, "by some elementary estimations, we get...", but do not mention how they get these.

I think Stirling's formula has been used although I could not really get these. Any help is appreciated.

EDIT: I "believe" Stirling's Approximation has been used, repeatedly, along with some other crude estimates. I am particularly having some problem figuring out how those estimates have been used.

I observe that for large $n$, by applying Stirling's Approximation, $${n\choose s}\sim \dfrac{e^{-s}n^{n+1/2}}{(n-s)^{n-s+1/2}s!}---(1)$$

$${{M-s(n-s)}\choose N_c}\sim \dfrac{e^{-N_c}{(M-s(n-s))}^{M-s(n-s)+1/2}}{{(M-s(n-s)-N_c)}^{M-s(n-s)-N_c+1/2}N_c!}---(2)$$

$${M\choose N_c}\sim \dfrac{e^{-N_c}M^{M+1/2}}{(M-N_c)^{M-N_c+1/2}}---(3)$$

Then, $(1)\times (2)/(3)$ is something, whose bound I want to make equal to the bounds given.

But things are getting too complicated by now. Please remember that $M={n\choose 2}$.