The equation is 0 = $25x^2$ - 30x + 58.
A = 25 , B = 30, C = 58
Using the quadratic formula (as shown in the picture) I get $\dfrac{{900\pm\sqrt{(-4900)}}}{ {50}} $. When I put it in the calculator (either the + or -, not both at the same time) I get "Non-Real Error". Is the answer not real?
The solution for this equation is imaginary solutions or complex solution. To check it, use the formula $b^2-4ac$.
If $b^2-4ac$ is more than 0, then it has different real solution. For instance, x = 2 and x = 3.
If $b^2-4ac$ is equal to 0, then it has same real solution. For instance, x = 3 and x = 3.
If $b^2-4ac$ is less than 0, then it has complex solution. For instance, $x = 2 + 3i$ and $x = 2 - 3i$ where i is referring to imaginary number or $\sqrt{-1}$
In this case, a = 25, b = -30 and c = 58. By using the formula: $$b^2-4ac=(-30)^2-4(25)(58)$$ $$b^2-4ac=900-5800$$ $$b^2-4ac=-4900 < 0$$
Hence it has complex solution or no real solution (no solution).
So, to solve it, just use Quadratic Formula: $$x=\frac{b \pm{\sqrt{b^2 - 4ac}}}{2a}$$ $$x=\frac{30 \pm{\sqrt{-4900}}}{50}$$ $$x=\frac{30 \pm{\sqrt{4900}i}}{50}$$ $$x=\frac{30 \pm{70i}}{50}$$ $$x=\frac{3 \pm{7i}}{5}$$ $$x=\frac{3+{7i}}{5},\frac{3-{7i}}{5}$$