Is the completion of a metrizable topological group metrizable?

444 Views Asked by At

Let $G$ be a topological group and its two-side uniformity $\mathcal{U}$ (that is the uniformity generated by right uniformity and left uniformity of $G$) coincides with the uniformity of a metric $d$ on $G$.

Evidently, the topological group is metrizable since the group topology is identical with the topology induced by $d$. Then the topological group $G$ equipped with two-side uniformity is isomorphic to (relatively to topological group structures) a dense subgroup of its completion $\hat{G}$ equipped with two side uniformity. I was wondering whether $\hat{G}$ is metrizable?

My attempt: Since metric $d$ is uniformly continuous on $G\times G$, we can uniquely extend this mapping to a uniformly continuous mapping $k:\hat{G}\times\hat{G}\rightarrow\mathbb{R}$. I proved $k$ is a pseudo-metric of $\hat{G}$ and the topology induced by $k$ is coarser than the topology of $\hat{G}$.

Any help is appreciated. Thanks.

1

There are 1 best solutions below

1
On BEST ANSWER

enter image description here

enter image description here

enter image description here enter image description here

(cited from Alexander V. Arhangel'skii, Mikhail G. Tkachenko, Topological groups and related structures, Atlantis Press, Paris; World Sci. Publ., NJ, 2008).