Is the isomorphism $V\to\mathbb K^{[\mathcal B]}$ always continuous?

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While trying to generalise the well-known result "continuous partials imply differentiability" to the case of infinite-dimensional spaces, the following question popped up in my work:

Let $V$ be a normed linear space over $\mathbb K$ with a basis $\mathcal B$. Is the induced isomorphism $T\colon V\to \mathbb K^{[\mathcal B]}$ continuous (with respect to any given norm on $\mathbb K^{[\mathcal B]}$)?

It's clear that for any norm $\lVert\cdot\rVert$ on $\mathbb K^{[\mathcal B]}$, there exists a norm on $V$, namely, $v\mapsto \lVert Tv\rVert$, which makes $T$ continuous: Just note that $T$ is a linear map which is bounded.

Thus, due to equivalence of norms on finite-dimensional vector spaces, if $\dim V < \infty$, then the answer to the posed question is affirmative.

However, I am unable to comment anything for a general norm on an infinite-dimensional $V$. Any ideas?