Is the order of $ab^{-1}$ larger than $m$?

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Let $F$ be a field, $a,b\in F^*$, the order of $a$ is $m$, the order of $b$ is $n$, $m>n>1$, $n\nmid m$ and $(m,n)>1$. Is the order of $ab^{-1}$ larger than $m$?

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Let $F=\Bbb Z/31\Bbb Z$, $g$ the generator of $F^*$, $a=g^2, b=g^{-3}$.