is the quadratic equation appropriate for this?

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I work in a paper mill as a tech. There is a formula for percent solvents in a liquor solution. It is s=(A*P^2) + (B*P) $S$ is the percent solvent, $A$ and $B$ are constants, $3.21953$ and $8.117$ respectively. I would like to solve for $p$, as instrumentation can tell me percent solvents, but I would like to verify the percentage for calibration purposes. I started moving stuff around and got confused, as college math classes were quite some time ago. I get that there is a squared variable there, so I have to square root something, and that percent solvents will never be negative, so that's probably an absolute value. This looks like a quadratic equation to me, if I replace the coefficients to $P^2$ and $p$ with $a$,$b$, and call percent solvents ($s$) $c$.

So then I subtracted $s$, and get $0= AP^2+Bp -C$. cool. So then I assumed I could use the quadratic equation, $P= \frac{-b \pm \sqrt{b^2+4ac}}{2a}$.

Is this a safe assertion? Or have I misused this formula?

(also if someone who knows how to format math on this website were to come tidy this up for me it would be much appreciated.

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Yes, this is how it would be done.

You would then have $\displaystyle P = \frac{-B \pm \sqrt{B^2-4As}}{2A}$.

When you evaluate both the $+$ and $-$, make sure you pick the $P$ for which the percent solvent makes sense physically.