Is the Space of Borel Probability Measures over R connected?

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I am trying to prove that the space $\mathcal{P}(\mathbb{R}^n)$ of Borel probability measures over $\mathbb{R}^n$ is separable, convex and most importantly connected.

I can show that $\mathcal{P}(\mathbb{R}^n)$ is a convex and seperable metric space when endowed with the Prokhorov metric (weak convergence, weak star topology). But I get stuck trying to prove that $\mathcal{P}(\mathbb{R}^n)$ is connected.

As $\mathcal{P}(\mathbb{R}^n)$ is convex, it seems intuitive to look at path-connectedness. So it would suffice to prove that for $\mu, \sigma \in \mathcal{P}(\mathbb{R}^n)$ the curve \begin{equation}\gamma: [0,1] \rightarrow \mathcal{P}(\mathbb{R}^n); \lambda \mapsto \lambda\mu + (1-\lambda)\sigma \end{equation} is continuous. But I have problems showing this.

My questions are:

  1. Is $\mathcal{P}(\mathbb{R}^n)$ connected?
  2. If not, I only need to this result for probability measures with finite suppport. Does it hold then.
  3. If $\mathcal{P}(\mathbb{R}^n)$ is connected, does this hold for more general cases? For example complete, separable, connected metric spaces.

I'd be very greatful for some help and sources that deal with this topic.

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In any topological vector space the linear operations are continuous, which implies that the curve you wrote is a continuous function of $\lambda$, and ultimately that all convex subsets are connected.

Consider the vector space of all signed measures on $\mathbb R^n$ with the same topology as the one you said in the question. Is it a topological vector space? If it is, then you're done as $\mathcal P(\mathbb R^n)$ is a convex subset of it.